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900x^2-600x+4=0
a = 900; b = -600; c = +4;
Δ = b2-4ac
Δ = -6002-4·900·4
Δ = 345600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{345600}=\sqrt{57600*6}=\sqrt{57600}*\sqrt{6}=240\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-240\sqrt{6}}{2*900}=\frac{600-240\sqrt{6}}{1800} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+240\sqrt{6}}{2*900}=\frac{600+240\sqrt{6}}{1800} $
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